[−][src]Function serde_json::from_reader
pub fn from_reader<R, T>(rdr: R) -> Result<T> where
R: Read,
T: DeserializeOwned,
Deserialize an instance of type T
from an IO stream of JSON.
The content of the IO stream is deserialized directly from the stream without being buffered in memory by serde_json.
When reading from a source against which short reads are not efficient, such
as a File
, you will want to apply your own buffering because serde_json
will not buffer the input. See [std::io::BufReader
].
Example
# use serde_derive::Deserialize;
use serde::Deserialize;
use std::error::Error;
use std::fs::File;
use std::io::BufReader;
use std::path::Path;
#[derive(Deserialize, Debug)]
struct User {
fingerprint: String,
location: String,
}
fn read_user_from_file<P: AsRef<Path>>(path: P) -> Result<User, Box<Error>> {
// Open the file in read-only mode with buffer.
let file = File::open(path)?;
let reader = BufReader::new(file);
// Read the JSON contents of the file as an instance of `User`.
let u = serde_json::from_reader(reader)?;
// Return the `User`.
Ok(u)
}
fn main() {
# }
# fn fake_main() {
let u = read_user_from_file("test.json").unwrap();
println!("{:#?}", u);
}
Errors
This conversion can fail if the structure of the input does not match the
structure expected by T
, for example if T
is a struct type but the input
contains something other than a JSON map. It can also fail if the structure
is correct but T
's implementation of Deserialize
decides that something
is wrong with the data, for example required struct fields are missing from
the JSON map or some number is too big to fit in the expected primitive
type.